In aerobic cellular respiration, if four molecules of pyruvic acid enter steps t

Question

In aerobic cellular respiration, if four molecules of pyruvic acid enter steps two, the formation of acetyl CoA and three, the Krebs cycle, how many molecules of ATP, NADH, and FADH2 will be formed? View Available Hint(s) 4 ATP, 12 NADH, 4 FADH2 2 ATP, 8 NADH, 2 FADH2 4 ATP. 16 NADH, 4 FADH2 1 ATP, 4 NADH, 1 FADH2 Submit ous Answ X Incorrect; One attempt remaining: Try Again Part Cyanide is a poison that induces cell death by preventing the electron transport chain from functioning. Which of the below statements best describes how cyanide kills cells View Available Hint(s) Without the movement of electrons through the electron transport chain, the hydrogen ion gradient is over produced, chemiosmosis occurs faster, speeding up the catabolic reactions of glucose and using up all the storage cellular ATP o Without the movement of electrons through the electron transport chain, the hydrogen ion gradient is not produced, chemiosmosis will not occur. Without chemiosmosis, the cell is unable to produce enough cellular ATP to survive. O Without the movement of hydrogen ions through the electron transport chain, the electron gradient is not produced, chemiosmosis will not occur. Without chemiosmosis, the cell is unable to produce enough cellular ATP to survive. Submit

Explanation / Answer

Answer to the top question is: 4 ATP, 16 NADH and 4 FADH2

1 Kreb cycle produces 3NADH,1FADH2 and 1 GTP/ATP.

3 cycles will make 9NADH,3FADH2 and 3ATP

Rest from oxidative decarboxylation step where pyryvic acid is converted into acetyl CoA.

Answer 2. Option 2,hydrogen ion gradient is not produced..

Cyanide acts on the cytochrome oxidase. Chemiosmosis works on the H ion concentration and that's gets hampered by cyanide thus, it is life threatening.

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