Negative charge is distributed uniformly along the FINITE line of charge shown.

Question

Negative charge is distributed uniformly along the FINITE line of charge shown. Using the symmetry of the problem, sketch the electric field vectors at the points indicated. (Your vectors don't have to be perfect in length, but they should point roughly in the correct direction.) Points #2 and #5 are across from the line's midpoint. Could you use a cylinder as a Gaussian surface for the finite line of charge? If so, explain and draw how you would orient the cylinder around the finite line of charge shown. If a cylinder would not work, explain why not.

Explanation / Answer

a) At 1 ,2 ,3 electric field vectors lines are perpendicularly towards line of charge in direction horizontally right .

    At 4 ,5 ,6 electric field vectors lines are perpendicularly towards line of charge in direction horizontally left .

b)    Yes, cylinder can be drawn around line of charge as Gaussian surface .

=>   E * ds = Q/eo

=> E * (2pi * r * L) = lambda * L/eo

=> E =    ( lambda )/(2pi * r * eo)

   

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