2- Data First falling time measurement: Falling time Second falling time measure

Question

2- Data First falling time measurement: Falling time Second falling time measurement Hanging mass ma-A0Ea3.000000S-kg Falling time t (sec) - ME-4 oooo.* Large disk mass M- Radius of the large disk R,0 Radius of the pulley atet e ds 9272o5 Computations For the computations, the mass of, and the effect of the two pulleys will be neglected 1. Using the equation y a? and the average value of t, find the acceleration of the falling mass for each of the two Radius ofthe large disk R-L67 Radius ofthe pulley attached to te lange disk .00Q2-" -2-_1.aes-m r masses. Using the radius of the pulley which holds the string compute the angular acceleration of the disk using a rad/s 2. Since the hanging mass is accelerating the tension in the string is less than the weight of the string. However, since t acceleration is very small; the tension in the string will be assumed to be approximately equal to the weight. The tor applied to the disk would then be approximately equal to the product of the weight of the hanging mass and the radir the pulley on the large disk: r- mgr. Compute the applied torque, then compute the moment of inertia / of the disk from the equation / =-

Explanation / Answer

1) Limits of uncertainties 0.153 , 0.167 , 0.172 .

2) Calculated value becomes larger than accurate values .

3)   Calculated value becomes smaller than true values .

4) Tension in string changes due to frictional force acting on the system .

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