You are traveling in a car going at a constant speed of 100 km/hr down a long, s

Question

You are traveling in a car going at a constant speed of 100 km/hr down a long, straight highway You pass another car going in the same direction which is traveling at a constant speed of 80 km/hr. As measured from your car's reference frame this other car is traveling at -20 km/hr. What is the acceleration of your car as measured from the other car's reference frame? What is the acceleration of the other car as measured from your car's reference frame? Give an explanation to your answers. Consider the following three cases. You try to push on a large box that has a mass equal to your mass across the floor. However, the box does not move due to friction. How do the magnitudes of the forces between you and the box compare to each other? You switch to a box that has a mass that is half of your mass and try to push it across the floor, but it also does not move. How do the magnitudes of the forces between you and the box compare to each other? You are able to place the box that has a mass half of your own onto a platform with wheels and you are able to push the box across the floor. How do the magnitudes of the forces between you and the box compare to each other? You apply a 2 Newton force to a 0.5 kilogram cart on a track and measure the acceleration of the cart with a motion detector The acceleration is measured to be equal to 3.5 meters/sec^2. Calculate the frictional force. In which direction compared to the applied force is it directed? You are back in your car and are driving at a constant speed around a curve Use Newton's 3 laws to explain the situation.

Explanation / Answer

1. As given in the problem both cars are moving in the same direction with constant speed , 100 km/hr, 80 km/hr.
   as measured from your car's reference frame this other car is travelling at - 20 km/hr.

   acceleration of the both the cars are zero , measured from any reference frame of the cars , because both are moving with constant speed.

2.

   if the applied froce is greater than the forces acting on the box then the box will displace or move ,

   a.F_y < F , F is forces acting on the box here as given F = F_g + F_f , force of gravity and frictional force

   b.F_y < F , F is forces acting on the box here as given F = F_g + F_f , force of gravity and frictional force

   c.F_y > F , F is forces acting on the box here as given F = F_g + F_f , force of gravity and frictional force

here there is no significance of mass of you its matter of how much force you applied .

3. F= ma

   given applied force is 2 N, mass of cart m = 0.5 kg,acceleration a = 3.5 m/s2

   F= 0.5*3.5 = 1.75 N remaining 0.25 N is frictional force acting on the cart in the opposite direction of the acceleration

4.   Newton's third law say for every force and action there is equal and opposite reaction

   here car is moving with constant speed around a curve , means no acceleration , then the force acting on the car is zero so that it can not fell down

   or the sum forces acting on it are equal to zero .

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