Then answer question1 Average Acceleration Trial 1 0.01137 ± 0.00001 Trial 2O. o
ID: 1417572 • Letter: T
Question
Then answer question1 Average Acceleration Trial 1 0.01137 ± 0.00001 Trial 2O. o 1342.0000 Trial 3 0.01492o.000 Trial 4 t 0,00 818 ± . 00001 Trial 5 t 0, 01350 ± 0.00001 Determine the average acceleration and its associated total uncertainty (show work). to: o 1312 ± 0.00001 m) 42-o.oe3.8-oans *._ o. 012 230, 06001 (-o.oli Sr_p013·t·0.0wy2-0 demoano -0,01 2 294 0.00001 m/s 0.012280.06001 m/s O. Question 1: Comment on what value of the acceleration that the cart has while it is moving at a constant speed. Include the range of values for the acceleration in your comment. constant speed. include the range of values frthe acceleration in yoExplanation / Answer
average acceleration= 0.012278 m/ss
total uncertainty= +/- 0.00005
Ques 1.
When the cart is moving at a constant speed, acceleration should theoretically be zero whereas the found one is of the order of 0.01 m/ss. Also range of this momentary acceleration seems to be varying from 0.00817 to0.01493 m/ss.
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