A cable lowers a 1150 kg elevator so that the elevator\'s speed increases from z

Question

A cable lowers a 1150 kg elevator so that the elevator's speed increases from zero to 4.0 m/s in a vertical distance of 6.4 m. What is the force that the cable exerts on the elevator while lowering it? (Assume that the system is the elevator and Earth.) Express your answer to two significant figures and include the appropriate units. What is the force that the cable exerts on the elevator while lowering it? (Assume that the system is the elevator only.) Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Here ,

m = 1150 Kg

v = 4 m/s

h = 6.4 m

part A) let the acceleration of the elevator is a

Using third equation of motion

v^2 - u^2 = 2 * a * d

4^2 = 2 * a * 6.4

a = 1.25 m/s^2

Fnet = m * (g + a)

Fnet = 1150 * (9.8 + 1.25)

Fnet = 12707.1 N

the force that the cable is 12707.1 N

part B)

while lowering the elevator ,

Fnet = m * (g - a)

Fnet = 1150 * (9.8 - 1.25)

Fnet = 9832.5 N

the force that the cable is 9832.5 N

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