Pulling a Block on an Incline with Friction A block of mass 1.00 kg sits on an i

Question

Pulling a Block on an Incline with Friction

A block of mass 1.00 kg sits on an inclined plane as shown.(Figure 1) A force of magnitude 30.0 N is pulling the block up the incline. The coefficient of kinetic friction between the plane and the block is 0.500. The inclined plane makes an angle 30.0 degreeswith the horizontal.

Part A What is the total work Wifric done on the block by the force of friction as the block moves a distance 9.00 I up the incline? Express the work done by friction numerically, in Joules 0? Submit Hints My Answers Give Up Review Part Part B What is the total work W done on the block by the applied foroe F as the block moves a distance 9.00 m up the incline? Express your answer numerically, in Joules. Submit Hints My Answers Give Up Review Part Now the applied force is changed so that instead of puling the block up the incline, the force pulls the block down the incline. (Figure 2) Part C What is the total work Wrc done on the block by the force of friction as the block moves a distance 9.00 Im down the incline? Express your answer numerically, in Joules. ?

Explanation / Answer

here,
mass of block, m = 1 kg
applied force, F = 30 N
coefficient of friction, u = 0.5

Work Done(w) = Force(f) * displacement * CosA

Part A:
wf = Fctional force * dip * Cos0
wf = u*mg*Cos30 * 9
wf = 0.5*1*9.81*Cos30*9
wf = 38.231 J

Part B:
wa = F * d * Cos0
wa = 30 * 9
wa = 270 J

Part C:
it will same as part (a) just now it is acting towards up the inclne
w = 38.231 J

Part D:
w = f * d * Cos0
w = (-30) * 9
w = 270 N

i.e same as part B, but acting down the incline

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