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A large capacitance of 1.08 mF is needed for a certain application. Calculate th

ID: 1416475 • Letter: A

Question

A large capacitance of 1.08 mF is needed for a certain application. Calculate the area the parallel plates of such a capacitor must have if they are separated by 4.81 mu m of Teflon, which has a dielectric constant of 2.1. What is the maximum voltage that can be applied if the dielectric strength for Teflon is 60 Times 10^6 V/m Find the maximum charge that can be stored. Calculate the volume of Teflon alone in the capacitor. What total capacitances can you make by connecting a 5.87 mu F and 6.89 mu F capacitor together? Find the total capacitance of the combination of capacitors shown in the figure below. (C_1 = 0.275 mu F, C_2 = 17.0 mu F.)

Explanation / Answer

8)

a)

C = k x epsilon A/d

substituting the given values we get

A = 279.515 m^2

b)

V = Ed

V = 4.81x60 = 288.6 Volts

c)

Q = CV

Qmax = 0.311688 C

d)

Volume = Ad

Volume = 0.001168 m^3

9)

series

Ceq = C!*C2/C1+C2

Ceq = 3.169 uF

parallel

Ceq = C1+C2

Ceq = 12.76 uF

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