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WileyPLUS https i) edugen. edugen/student/mainfr.unl WileyPLUS: MywileyPLUS I Help I Contact Us I Log o S Cutnell, Physics, 10e General Physics I and II (PHY101/10 actice Gradebook ORION nment HESSAGE HY ENSTRUCTOR FULL SCREEN PRINTER VERSION BACK Chapter 04, Problem 003 GO Two horizontal forces, E, and E, are acting on a bax, but only is shown in the drawing. can point either to the right or to the left The box moves only along the x axis. There is no friction between the box and the surface. Suppose that +7.0 N and the mass of the box is 4.2 kg. Find the magnitude and direction of F2 when the acceleration of the box is (a) +6.1 m/s, (b)-6.1 m/s, and (c) m /s? (b) F Click if you would like to Show Work for this question: Open Show Work By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor Question Attempts: Unlimited SAVE FOR LATER Version 4.18 12 MacBook o0 F7 F8 FIO

Explanation / Answer

From the Newton's second law of motion accleration is

a = F net/m = F1/m + F2/m = 7 N/4.2 kg + F2/4.2 kg = 1.66 m/s^2 + F2/ 4.2 kg

(a)

when a = 6.1 m/s^2

6.1 m/s^2 = 1.66 m/s^2 + F2/ 4.2 kg

F2 = 18.64 N

(b)

a = -6.1 m/s^2

-6.1 m/s^2 = 1.66 m/s^2 + F2/ 4.2 kg

F2 = -32.592 N

(c)

a = 0

0= 1.66 m/s^2 + F2/ 4.2 kg

F2 = -6.972 N

As per guide lines I worked first problem please post remaining posts in the next question

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