72% Sat Jun 11 11 01 18 AM a E Chrome File Edit View History Bookmarks People Wi

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72% Sat Jun 11 11 01 18 AM a E Chrome File Edit View History Bookmarks People Window Help Josh Motion in multiple dimens C Chegg Study I Guided Sol www.webassign.net /web/Student/Assignment-Responses/last?dep 13907358 Apps Bookmarks Apple YouTube home Watch Live Sports E O tech Destiny l The BNg faculty.pnc.edu/ptes OTR DestinyTracker De nyLFG.N Eii C. Henry Edwards, -1 -2 -1 -12 -16 (0.0%) Points Assignment submission For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer. Assignment Scoring Your last submission is used for your score. 1. -1 points CJ10 3. 014. My Notes Ask Your Teacher As a tennis ball is struck, it departs from the racket horizontally with a speed of 27.8 m/s. The ball hits the court at a horizontal distance of 19.2 m from the racket. How far above the court is the tennis ball when it leaves the racket? Additional Materials Section 3.3 2. -2 points CJ10 3. 015 My Notes Ask Your Teacher A skateboarder shoots off a ramp with a velocity of 6.5 m/s, directed at an angle of 55 the The above horizontal. end of the ramp is 1.3 m above the ground. Let the x axis be parallel to the ground, the y direction be vertically upward, and take as the origin the point on the ground directly below the top of the ramp (a) How high above the ground is the highest point that the skateboarder reaches? b) When the skateboarder reaches the highest point, how far is this point horizontally from the end of the ramp?

Explanation / Answer

t = D/V = 19.2/27.8 = 0.690sec

Y = ½g*t² = 2.467 m

= 0.5*9.8*0.690^2

= 2.332 m

U = 6.5m/s at 55°
Ux = 6.5cos55 = 3.72m/s
Uy = 6.5sin55 = 5.32m/s
g = 9.8m/s²

a)
max height is when Vy = 0 so
0 = Vy² = Uy² - 2gy
gives the max height as
y = Uy²/(2g) = 5.32²/19.6 = 1.44m

b) also if Vy=0 then
0 = Vy = Uy - gt
so the time is takes to reach max height is
t = Uy/g
then the horizontal distance is
x = Uxt = UxUy/g = 2.01 m

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