To understand how to compute power dissipation m a resistive circuit (Figure 1)

Question

To understand how to compute power dissipation m a resistive circuit (Figure 1) The circuit in the diagram consists of a battery with EMF epsilon, a resistor with resistance R. an ammeter, and a voltmeter The voltmeter and the ammeter (labeled V and A, respectively) can be considered ideal; that is. the resistances are infinity and zero, respectively The current in the resistor is I, and the voltage across it is V The internal resistance of the battery r is not zero What is the power P_R dissipated in the resistor? Express your answer In terms of I and V. Again what is the power dissipated in the resistor? This time, express your answer In terms of one or more of the following variables: I and r_int and R.

Explanation / Answer

Part C,
Power dissipated in the Resistor, PR = V*I

Part D,
Substituing Values in above eq,

Where V = e - I*rint

So,
PR = I*(e - I*rint)

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.