( 48 025 ) 3.5 0) 34 d 2.5 ms 10 A 8.20 g ojet atached so a at e spring with spr
ID: 1414555 • Letter: #
Question
( 48 025 ) 3.5 0) 34 d 2.5 ms 10 A 8.20 g ojet atached so a at e spring with spring constant A- 10 N/m, is moving on a n simple harmonic motion of amplitude of 0.080 m. What is whens ins digplacement is 0 040 m7 fint: Use conservation of energy d. 24.5 cs of a 0.64-4g mass ng simple harmonic motion is given by " 11. The position of a to 1° (O 160 m) cos (m/16). what is its periodoroscillation?, (nU/16). What is its period of oscillation? a. 100 s b. 32 c, 16 s d. 8.0 has a period of 2.0 s. What is the pendulum length? (-9.8 m/s ? (g 9.8 m/s?) 12. A simple a. 0.36 m b. 0.78 m c. 0.99 m d. 2.4 m 13. 4 2 0m long piano sring of mss 0 g is under a tension of 338 N. Find the speed with which a wave travels on this string. a. 130 m/s b. 260 m/s c. 520 m/s d. 1 040 m/s 14. What is the intensity level of a sound with intensity of 5.0 x 10-10 W/m"? (1,-10"12 W/) a. 74 dB b.54 dB c. 2.7 dB d. 27 dBExplanation / Answer
8)
wavelength = speed of wave * time
wavelength = 12 m/s * 0.25 s
wavelength = 3 m
option c)
9)m = 0.20 Kg
k = 10 N/m
x = 0.050 m
let the acceleration is a
m * a = k * x
0.20 * a = 10 * 0.050
a = 2.5 m/s^2 option d)
10)
m = 0.20 Kg
k = 10 N/m
Using conservation of energy
0.5 * m * v^2 + 0.5 * k * x^2 = 0.5 * k * A^2
0.20 * v^2 + 10 * 0.040^2 = 10 * 0.80^2
solving for v
v = 49 m/s = 49 cm/s
option c. 49 cm/s
11)
here, w = pi/16 rad/s
period of oscillation = 2pi/w
period of oscillation = 2pi/(pi/16)
period of oscillation = 32 s
11)
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