3) A centrifuge spins a solution of particles in order to separate particles of

Question

3) A centrifuge spins a solution of particles in order to separate particles of different masses. A certain particle must spin at 34,000 rpm at a radius of 6.9 cm from the center of rotation before it will adequately separate in the solution. a) What is the linear speed of particle as it rotates? the b) How many g's of acceleration are required for particle separation? Chose a planet further from the Sun than Earth and use the Solar System Data in your textbook to determine: 4. a) the centripetal acceleration of the planet assuming a circular orbit about the Sun b) the centripetal force acting on the planet to maintain its orbit (which would be equal to the gravitation force of the

Explanation / Answer

a)

F = G * m1 * m2 / r^2

G = gravitational constant of the universe
m1 = mass of first object
m2 = mass of second object
r = distance between the 2 object's centers

G = 6.67428 x 10^-11 m^3 / (kg * s^2)
m1 = 1.9891 x 10^30 kg
m2 = 6.4185 x 10^23 kg
r = (I'll use the average distance) 2.3 x 10^8 km

(6.67428 x 1.9891 x 6.4185 x 10^-11 x 10^30 x 10^23) / (2.3 x 10^8)^2
(6.67428 x 1.9891 x 6.4185 x 10^-11 x 10^30 x 10^23) / (5.29 x 10^16)
(8.5210788718638 x 10^43) / (5.29 x 10^16)
1.6107899568740642722117202268431 x 10^27 Newtons

1.611 x 10^27 Newtons ( answer )

centrepetal acceleration

a = F/mas of mars = 2492.79 m/s^2

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