The circuit shown In the figure below is used to make a magnetic balance to weig
ID: 1413944 • Letter: T
Question
The circuit shown In the figure below is used to make a magnetic balance to weigh objects. The mass m to Oe measured is hung from the center of the bar, that s in the uniform magnetic field of 1.67 T, directed into the plane of the figure. The battery voltage can be adjusted to vary the current In the circuit. The horizontal bar Is 66 3 cm long and is made of extremely ght-wetght manual. It is connected to the battery by this vertical wrest that can support no appreoaNe tension; all the weeghc 0/the suspended mass m is supported by the magnetic force on the bar A resistor with is = 5.00 II is in scr.es with the bar; the resistance of the re oi the circuit H much less than this. Which point, a or b, should be the positive terminal of the battery?Explanation / Answer
The force on a current carrying wire due to a magnetic field is given by the equation
F = i(l x B)
As the rod is perpendicular to the magnetic field the magnitude of the force is given as
F = BiL
a)
For the force to balance the weight it should be upward, for that the current in the rod must be from left to right and hence the point a must be connected to the positive terminal of the battery.
b)
The maximum current in the rod I = V/R = 175 / 5 = 35 A
Maximum force acting on the rod is F = BiL = 1.67 x 35 x 0.663 = 38.7524 N
Hence the greatest mass measured will be m = W / g = 38.7524 / 9.8 = 3.9543 kg
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