A charged dust particle of mass m has 1000 excess electrons on it. The dust part

Question

A charged dust particle of mass m has 1000 excess electrons on it. The dust particle is suspended at rest in a uniform electric field a few meters above the earth's surface. The gravitational force acting on the dust particle is equal to mg, where g is the acceleration due to gravity near the Earth's surface. Which of the following statements must be true if the dust particle remains suspended at rest? Note that the elementary charge is represented by e, where e = 1.6*10-19 C. There are 3 correct answers. A. The electric field is directed in the upward direction. B. The dust particle has a net positive charge. C. The magnitude of the electrostatic force is equal to mg, the magnitude of the gravitational force. D. The dust particle experiences an upward electrostatic force. E. The magnitude of net charge of the dust particle is 1.6*10-19 C. F. The magnitude of the electric field can be calculated by dividing mg by 1000 e.

Explanation / Answer

here

the correct answers is

C.

The magnitude of the electrostatic force is equal to mg, the magnitude of the gravitational force

E.

the magnitude of net charge of the dust particle is 1.6 * 10^-19C

D.

the dust particle experieneces an upward electrostatic force

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