A square wire loop 13.0 cm on each side carries a clockwise current of 13.5 A. F
ID: 1413701 • Letter: A
Question
A square wire loop 13.0 cm on each side carries a clockwise current of 13.5 A. Find the magnitude and direction of the magnetic field at its center due to the four 1.40-mm wire segments at the midpoint of each side. (Assume the loop lies in the plane of the screen.)
A square wire loop 13.0 cm on each side carries a clockwise current of 13.5 A. Find the magnitude and direction of the magnetic field at its center due to the four 1.40-mm wire segments at the midpoint of each side. (Assume the loop lies in the plane of the screen.) magnitude direction Select into the screen out of the screenExplanation / Answer
From Biot Savarts law
B=uo*I*L/4pi*r2
Total Magnetic fiekd created by four segments
Btotal=B1+B2+B3+B4=4B
Btotal=4*(4pi*10-7)*13.5*(1.4*10-3)/4pi*(0.13/2)2
Btotal = 1.789*10-6 T
Direction is into the screen
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