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A square wire loop 13.0 cm on each side carries a clockwise current of 13.5 A. F

ID: 1413701 • Letter: A

Question

A square wire loop 13.0 cm on each side carries a clockwise current of 13.5 A. Find the magnitude and direction of the magnetic field at its center due to the four 1.40-mm wire segments at the midpoint of each side. (Assume the loop lies in the plane of the screen.)

A square wire loop 13.0 cm on each side carries a clockwise current of 13.5 A. Find the magnitude and direction of the magnetic field at its center due to the four 1.40-mm wire segments at the midpoint of each side. (Assume the loop lies in the plane of the screen.) magnitude direction Select into the screen out of the screen

Explanation / Answer

From Biot Savarts law

B=uo*I*L/4pi*r2

Total Magnetic fiekd created by four segments

Btotal=B1+B2+B3+B4=4B

Btotal=4*(4pi*10-7)*13.5*(1.4*10-3)/4pi*(0.13/2)2

Btotal = 1.789*10-6 T

Direction is into the screen

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