In a game of pool, the cue ball struck another ball of the same mass that was in

Question

In a game of pool, the cue ball struck another ball of the same mass that was initially at rest.After the collision, the cue ball moved off at 3.30 m/s along a line that was at 18° from the cue ball’s original path.The second ball had a speed of 2.20 m/s after the collision.

Find the angle between the cue ball’s original direction of motion and the second ball’s direction of motion after the collision.

Find the original speed of the cue ball.

If the mass of the cue ball is 0.150 kg, what is the change in kinetic energy?

((I need readable solution please))

Explanation / Answer

The moments must be preserved in both directions. In this case as the masses are equal the velocities must be preserve. Perpendicular to the original speed, the speeds must be opposite.
3.20.sin(18) = 2.20*sin(a)
sin(a) = 0.4495
a = 26.7 degrees up from x-axis.
AS kinetic energy is preserved, and masses are equal.

v^2 = v1^2 + v2^2 (v being the velocity before collision)
v = 3.62 m/s

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