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ID: 1412275 • Letter: 1

Question

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Explanation / Answer

Here,

time , t = 19.5 s

acceleration, a = 2.8 m/s^2

a) let the distance travelled is d

Using second equation of motion

d = 0.5* a * t^2

d = 0.5 * 2.8 * 19.5^2

solving for d

d = 532.4 m

the distance travelled is 532.4 m

b)

Using first equation of motion

v = a * t

v = a* t

the final speed is a * t

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