(790) Problem 4: A car begins at rest at to-0. The car starts moving and finally
ID: 1412164 • Letter: #
Question
(790) Problem 4: A car begins at rest at to-0. The car starts moving and finally covers a distance d= 992 m in a time tr= 185 s. In a coordinate system with north being the positive x-direction, the car's motion is in the southern direction (see figure) south(-x north( time, t,0 ©theexpertta.com 25% Part (a) What was the car's average speed during this period, n meters per second? -.. 25% Part (b) What was the car's displacement in the x-direction . in meters, during this period? Grade Summa Deductions Potential 096 100% Submissio Attempts remaining: 3 (15% per attempt) detailed view si1n cos ns cotan0 asin0 atan acotan sihO cosh0 cotanhO ac END Degrees Radians NO DEL CLEAR Submit Hint I give up! Hints: 5% deduction per hint. Hints remaining: 2 Feedback: 5% deduction per feedback. - 25% Part (c) What was the car's average velocity varg. In meters per second. during this period? - 25% Part (d) If the car's final velocity at tf was vf=-30.0 m s what was the car's average acceleration aavg in meters per square second. during this period?Explanation / Answer
vi = 0
d = 992 m
tf = 185 s
(b)
Car's displacement in x direction = - 992 i^ m
(c)
Car's Average Velocity, Vavg = -992/185 i^
Vavg = -5.36 i^ m/s
(d)
Vf = - 30.0 m/s
We know,
Average acceleration, aavg = (Change in Velocity)/(Change in time)
Average acceleration, aavg = (- 30.0 - 0)/(185 - 0)
aavg = -0.162 m/s^2
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