A jumper leaves ice ground at an angle of 30o above the horizontal and at a spee

Question

A jumper leaves ice ground at an angle of 30o above the horizontal and at a speed 50m/s. How tar does he jump in the horizontal direction? (b) What is the maximum hegira Determine the magnitude and direction of his velocity and position after 2 s. Ball A is thrown upwards with initial speed of 100 m/s Bails released from rest fry of 4 m. At what time and distance do they pass each other? A particle starts from rest and accelerates as shown in figure 2 Determine (a) the p speed at t=6 s and t = 16 s and (b) the distance traveled in the first 16 s.

Explanation / Answer

a) in vertical, he finally comes to gorund(same vertical position ))

so displacement in vertical direction = 0

initial vertical velocity, uy = 50sin30 = 25 m/s

Applying d = uy t + at^2/2

0 = 25t - 9.8t^2 /2

t = 2.26 sec

horizontal distance, d = 50cos30 * 2.26 = 97.8 m

b) maximum height will be when vertical velocity component will become zero.
vf^2 - vi^2 = 2 a h

0^2 - (50sin30)^2 = 2(-9.8)(H)

H = 31.9 m

c) vx = ux = 50cos30 = 43.3 m/s

vy = 25 - 9.8(2) = 5.4 m/s

magnitude = sqrt(vx^2 + vy^2) = 43.6 m/s

direction = tan^-1(vy/vx) =7.11 deg above

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.