I already got these answers (below the box) and they were wrong. Please help. A
ID: 1410867 • Letter: I
Question
I already got these answers (below the box) and they were wrong. Please help.
A certain particle is sent into a uniform magnetic field, with the particle's velocity vector perpendicular to the direction of the field. The figure gives the period T of the particle's motion versus the inverse of the field magnitude B. The vertical axis scale is set by T_s= 22.4 ns, and the horizontal axis scale is set by B^-1_S = 4.4 T^-1. What is the ratio m/q of the particle's mass to the magnitude of its charge?Explanation / Answer
1/Bs =4.4T^-1
Bs =1/4 =0.23 T
Ts=2pim/qBs
=>m/q =Ts*Bs/2pi
m/q =(22.4*10^-9)*0.23/2pi
m/q =8.20*10^-10 kg/C
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