BACK Chapter 15, Problem 007 Your answer is partially correct. Try again. In exe
ID: 1410746 • Letter: B
Question
BACK Chapter 15, Problem 007 Your answer is partially correct. Try again. In exercising, a weight lifter . (a) Assuming that the latent heat of vaporization of perspiration is 2.42 x 10o Vkg, find the loses 0.221 kg of water through evaporation, the heat required to evaporate the water evaporation, the heat required to evaporate the water coming from the weight liter's body. The work done in lifting weights is 1.82 x 10 (a) Assuming that the latent heat of vaporization of perspiration is 2.42 x 100 J/kg, find the change in the internal energy of the Calories of food that must be consumed to replace the loss of internal energy.(1 nutritional Calorie 4186 3). weight lifter. (b) Determine the minimum number of nutritional (a) Number 719820 (o) Number 71920 Units (b) Number Open Show Work Click If you would like to Show Work for this question:Explanation / Answer
from the first law of thermodynamics the change in internal energy of the weight lifter is
delU = Q- W
= - mL_v - W
=-0.221 (2.42 * 10^6 J/kg) - 1.85 * 10^5 J
=-7.19 * 10^5 J
(b)
1 nutritional calorie = 4186 J
th enumber of nutritional calorie is
7.19 * 10^5 J ( 1 Calorie/ 4186 J) = 171.95 nutritional calories
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