A photon of orange light, wavelength of 600 nm, enters a calcium atom in the E6

Question

A photon of orange light, wavelength of 600 nm, enters a calcium atom in the E6 excited state and ionizes the atom. What kinetic energy will the electron have as it is ejected from the atom? A photon of orange light, wavelength of 600 nm, enters a calcium atom in the E6 excited state and ionizes the atom. What kinetic energy will the electron have as it is ejected from the atom? A photon of orange light, wavelength of 600 nm, enters a calcium atom in the E6 excited state and ionizes the atom. What kinetic energy will the electron have as it is ejected from the atom?

Explanation / Answer

We know that the ionisation energy of calcium is 6.08 eV and the enregy of E6 is 5.18 eV Hence the electron's work function will be 6.08 - 5.18 = 0.9eV

And the energy of the orange photon is =1240/600 = 2.06eV

HEnce the maximum KE will be

KE max = 2.06 - 0.9 = 1.16 eV

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