the work function for potassium is 2.24 eV. If the potassium metal is illuminate
ID: 1410497 • Letter: T
Question
the work function for potassium is 2.24 eV. If the potassium metal is illuminated with light of wavelength 400 nm, (a) find the maximum kinetic energy of the photoelectrons and (b) the cutoff wavelength . the work function for potassium is 2.24 eV. If the potassium metal is illuminated with light of wavelength 400 nm, (a) find the maximum kinetic energy of the photoelectrons and (b) the cutoff wavelength . the work function for potassium is 2.24 eV. If the potassium metal is illuminated with light of wavelength 400 nm, (a) find the maximum kinetic energy of the photoelectrons and (b) the cutoff wavelength .Explanation / Answer
A) KEmax = h xc / lambda - work function
KEmax = 1.24/0.32 - 2.24 = 1.635 eV
B) Cutoff
KEmax = 0 = h c / lambda - work function
lambda_cutoff = h c / work function
lambda_cutoff = 1.24 / 2.24 = 0.553 um = 553 nm
Ans a) maximum kinetic energy of the photoelectrons is 1.635 eV
b) the cutoff wavelength is 553 nm
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