two masses ma 4.8 and mb collide in a totally in elastic collision ma initial sp
ID: 1410496 • Letter: T
Question
two masses ma 4.8 and mb collide in a totally in elastic collision ma initial speed 7.2 m/s mb is 9.6 kg with of initial speed -3.6 m/s. a. what is the speed and direction of the combined mass after collision b. what is the initial and final kinetic energy c. what percentage of kinetic that was lost in the collision? two masses ma 4.8 and mb collide in a totally in elastic collision ma initial speed 7.2 m/s mb is 9.6 kg with of initial speed -3.6 m/s. a. what is the speed and direction of the combined mass after collision b. what is the initial and final kinetic energy c. what percentage of kinetic that was lost in the collision?Explanation / Answer
A) By momentum conservation,
ma va + mb vb =(ma+mb)*v
4.8*7.2 -9.6*3.6 = (4.8+9.6) v
v = 0
Hence speed is 0 m/s
B) initial KE = 0.5*4.8*7.2*7.2 + 0.5*9.6*3.6*3.6 = 186.624 J
Final KE = 0.5 m v^2 = 0 J
C) percentage of KE lost = (186.624-0)/186.624 *100
= 100 %
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