According to the U.S. Energy Information Administration, the United States gener

Question

According to the U.S. Energy Information Administration, the United States generated approximately 4.12×1012 kWh of electrical energy during 2010. If we could generate all this energy using a matter-antimatter reactor, how many kilograms of fuel would the reactor need, assuming 100% efficiency in the annihilation?

Answer to this first one is 1.65x10^2kg

Now what is the answer to the second one?

Suppose the fuel consisted of lead and anti-lead, each of density 11300 kg/m3. If the lead and anti-lead were each stored as a cubical pile, what would the side-length of each cube be?

Explanation / Answer

Here ,

energy produced = 4.12 *10^12 kWh

energy produced = 4.12 * 10^12 * 3600 * 1000 J

Let the mass needed is m

energy produced = m * c^2

4.12 * 10^12 * 3600 * 1000 = m * (3 *10^8)^2

m = 165 Kg

the mass used is 165 Kg

density of lead , p = 11300 Kg/m^3

volume of cube = mass/density

a^3 = 165/11300

a = 0.244 m

the length of each cube is 0.244 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.