-7 -6 5 -4 3 2 -1 0 2 34 5 6 7 The scale along the bottom of the figure is in ce
ID: 1409350 • Letter: #
Question
-7 -6 5 -4 3 2 -1 0 2 34 5 6 7 The scale along the bottom of the figure is in centimeters. What is the distance 2x3 between the third maxima in the intensity pattern? Note: the central peak is the "zeroth maximum", the two peaks closest to this on either side are the "first maxima", the next two peaks are the "second maxima", etc. (Units required, and you must be within 1 mm to be correct.) The slit-to-screen distance is D- 1.400 m, and the slit separation is 0.142 mm. Use the formula for double-slit diffraction maxima and your value of 2x3 to find the light source's wavelength . (Units required.) If the light source's wavelength were set to 535 nm, but everything else left the same, what would the distance between the second maxima 2x2 become? (Units required.) when = 535 nm then 2x2 =Explanation / Answer
a) Here, distance 2x3 = 2 * 2 = 4 cm
b) Here, d * sin(theta) = n * lambda
=> d * (x3/D) = n * lambda
=> 0.142 * 10-3 * (0.02/1.4) = 3 * lambda
=> lambda = 676.2 nm
=> wavelength , lambda = 676.2 nm
c) Here, d * (x2/D) = n * lambda
=> 0.142 * 10-3 * (x2/1.4) = 2 * 535 * 10-9
=> x2 = 1.055 cm
=> 2x2 = 2.11 cm
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