two cars start at the same location and accelerate for the same amount of time.

Question

two cars start at the same location and accelerate for the same amount of time. if one car has twice the acceleration for the other, how will the final speeds of the cars compare? by how much farther will the faster car outdistance the slower car?

two cars start at the same location and accelerate for the same amount of time. if one car has three times the acceleration for the other, how will the final speeds of the cars compare? by how much farther will the faster car outdistance the slower car?

Explanation / Answer

initial speed of both the cars =0

let acceleration of first car is a m/s^2 and acceleration of second car is 2*a m/s^2

let they have travelled for t seconds.

then final speed of first car=initial speed+acceleration*time=0+a*t=a*t

final speed of second car=0+2*a*t=2*a*t

hence final speed of second car is double the final speed of first car.

similarly as distance covered=initial speed *time+0.5*acceleration*time^2

second car will move twice the distance as compared to first car.

part 2:

if acceleration of one car is three times the other, final speed will be three times the other and distance travelled will also be three times the other.

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