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Your answer is partially correct. Try again The figure shows the transverse velo

ID: 1407571 • Letter: Y

Question

Your answer is partially correct. Try again The figure shows the transverse velocity u versus time t of the point on a string at x 0, as a wave passes through it The scale on the vertical axis is set by us 4 m/s. The wave has form y(x, t) ymsin (kx wt p). What is p in the range from w to +ar (Caution: A calculator does not always give the proper inverse trig function, so check your answer by substituting it and an assumed value of p into y(x, t) and then plotting the function.) u (m/s) 876298 rad the tolerance is +/-2%

Explanation / Answer

at t = 0 s

and x = 0

y = ym * sin(kx - w*t + phi)

v = vm * cos(kx - w*t + phi)

Now , for t = 0 , x = 0

-0.8 * vm = vm * cos(phi)

cos(phi) = -0.8

phi = 2.497 radians

the phase angle phi is 2.497 radian

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