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an archer shoots an arrow vertically upward adjacent to 40 m verticle castle wal

ID: 1406596 • Letter: A

Question

an archer shoots an arrow vertically upward adjacent to 40 m verticle castle wall with a speed of 25.7 m/s from height of 12m above ground.
A. How far above top if wall does arrow fly? Show max height B. Find speed of arrow at vertical position at top of wall C. How much time elapse from time arrow is shot to vertical position of top of wall on the way down an archer shoots an arrow vertically upward adjacent to 40 m verticle castle wall with a speed of 25.7 m/s from height of 12m above ground.
A. How far above top if wall does arrow fly? Show max height B. Find speed of arrow at vertical position at top of wall C. How much time elapse from time arrow is shot to vertical position of top of wall on the way down an archer shoots an arrow vertically upward adjacent to 40 m verticle castle wall with a speed of 25.7 m/s from height of 12m above ground.
A. How far above top if wall does arrow fly? Show max height B. Find speed of arrow at vertical position at top of wall C. How much time elapse from time arrow is shot to vertical position of top of wall on the way down

Explanation / Answer

initial velocity voy = 25.7 m/s


initial position yo = 12m

acceleration ay = -9.8 m/s^2


A)


final v

at maximum height

final velocity vy = 0

vy^2 - voy^2 = 2*g*(ymax-yo)


ymax = voy^2/2g

ymax = yo + voy^2/2g

ymax = 12 + (25.7^2/19.6) = 45.7 m


distance above the top of the wall = ymax - 40 = 5.7 m <<<----------answer

B)

for dy = 40-12 = 28m

vy^2 - voy^2 = -2*a*dy


vy^2-25.7^2 = -2*9.8*28

vy = 10.57    <<<----------answer

(C)


while coming down velocity at top = vy = -10.57


vy = voy + a*t

-10.57 = 25.7 - 9.8*t


t = 3.7 s <<<----------answer