a bullet traveling horizontally at a speed of 370 m/s hits a board perpendicular

Question

a bullet traveling horizontally at a speed of 370 m/s hits a board perpendicular to its surface, passes through and emerges on the other side at a speed of 210 m/s.
If the board is 4.20 cm thick, how long does the bullet take to pass through it?
t= __ s a bullet traveling horizontally at a speed of 370 m/s hits a board perpendicular to its surface, passes through and emerges on the other side at a speed of 210 m/s.
If the board is 4.20 cm thick, how long does the bullet take to pass through it?
t= __ s a bullet traveling horizontally at a speed of 370 m/s hits a board perpendicular to its surface, passes through and emerges on the other side at a speed of 210 m/s.
If the board is 4.20 cm thick, how long does the bullet take to pass through it?
t= __ s

Explanation / Answer

here

the board is thick h = v1 * t - 0.5 * a * t^2

a = (v1 - v2) / t and there v1=370 m/s, v2 = 210 m/s, t is time in question, h=0.042 m;

thus 0.042 = 370 * t – 0.5 * (370 - 210)*t

then

t = 2 * 0.042 / (370 + 210) = 0.0001448 s

so the time taken by the bullet to pass the board is 0.0001448 sec

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