x = 1.99 + 3.02 t 1.00 t 2 , where x is in meters and t is in seconds. (a) Find
ID: 1406070 • Letter: X
Question
x = 1.99 + 3.02t 1.00t2,
where x is in meters and t is in seconds.
(a) Find the position of the particle at t = 2.80 s
_______m
(b) Find its velocity at t = 2.80 s.
______ m/s
(c) Find its acceleration at t = 2.80 s.
______ m/s2
2)The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of -5.20 m/s2 for 4.15 s, making straight skid marks 63.1 m long, all the way to the tree. With what speed does the car then strike the tree?
_______ m/s
Explanation / Answer
1)
x = 1.90 + 3.02 t - 1 t^2
a) for t = 2.80 s
x = 1.90 + 3.02 * 2.80 - 2.80^2
x = 2.516 m
the postion of particle is 2.516 m
b) as velocity is
v = dx/dt
v = 3.02 - 2 * t
for t = 2.80 s
v = 3.02 - 2 * 2.80
v = -1.78 m/s
the speed of particle at 2.80 s is -1.78 m/s
c)
as acceleration , a = dv/dt
a = -2
at t = 2.80 s
a = -2 m/s^2
the acceleration of the particle is -2 m/s^2
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