Print i Calculator Periodic Table Question 5 of 15 Map sapling learning A 0.6630

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Print i Calculator Periodic Table Question 5 of 15 Map sapling learning A 0.6630-kg ice cube at 12.40°C is placed inside a chamber of steam at 365.0°C. Later, you notice that the ice cube has completely melted into a puddle of water. If the chamber initially contained 6.910 moles of steam (water) molecules before the ice is added, calculate the final temperature of the puddle once it settled to equilibrium. (Assume the chamber walls are sufficiently flexible to allow the system to remain isobaric and consider thermal losses/gains from the chamber walls as negligible.) Number 90.379 Previous O Next E S Give Up & View Solution Check Answer xit Hint Set an expression describing the energy required to raise the temperature of the ice to the equilibrium temperature equal to another expression describing the total energy released by the steam as it cools toward the equilibrium temperature. Then solve for the equilibrium temperature. Use the following values for the heat capacities of ice, water, and steam. clee 2034 J/(kg oc) cwarer 4186 J/ (kg oc) c,team 2029 J /(kg oc)

Explanation / Answer

mass of steam , ms = 6.910 * 18

ms = 124.4 gm

ms = 0.1244 Kg

let the final temperature is Tf

energy lost by steam = energy gain by ice

0.1244 *( (365 - 100) * 2029 + 2260 *10^3 + 4186 *(100 - Tf )) = 0.6630 *(12.40 * 2034 + 334 *10^3 + 4186 *(Tf))

soving for Tf

Tf = 49.13 degree C

the final temperature of the mixture is 49.13 degree C

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