(a) We choose x = 0 to be the initial location of the first player, and t = 0 to
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Question
(a) We choose x = 0 to be the initial location of the first player, and t = 0 to be the instant when this player starts to chase his opponent. At this time, the opponent is (2.10 s).(3.0 m/s) 6.3 m in front of the first player. We are given that the first player accelerates uniformly at 0.37 mIs2 At time t> 0 the displacements of the first player and his opponent from the origin are When the players are side by side, Xplayer = Xopponent. Equating the right-hand sides of the two equations from the previous step, we have When we simplify into the quadratic form at^2 + bt + c = 0 where a = 1, we have the following quadratic equation in the variable t. Remember to pay attention to the signs of the coefficient and constant when entering the answers.Explanation / Answer
(1/2) 0.37 t^2 = 6.3 + 3t
(1/2) 0.37 t^2 - 6.3 - 3t =0
0.185 t^2 - 6.3 - 3t =0
t^2 - (6.3/0.185) - (3/0.185) t =0
t^2 - (3/0.185) t -(6.3/0.185) =0
t^2 - (16.216) t -(34.054) =0
a = 1
b = -16.216
c= - 34.054
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