2. The following are dihybrid testcross data. Do these data approximate the rati

Question

2. The following are dihybrid testcross data. Do these data approximate the ratio one would expect for independent assortmente Complete the table, calculate the ' and answer the questions related to your calculations Phenotype co-E O-EVE O-E 4-B- 102 4-bb 61 aaB- 71 aahb 97 Totals a. In interpreting this x value, you have b. In this case, do you accept/reject the hypothesis that these data approximate the dihybrid test- degrees of freedom. cross ratio with independent assortment? C. what is the probability that the deviations are due to chance alone? Complete the following table for the data given in this problem. Note that the data in this prob- lem are dihybrid testcross data. Now, determine whether each gene pair is behaving individu- ally as you would expect in a monohybrid testcross. Each trait considered individually should be expected to approximate a 1:1 ratio as a consequence of Mendel's law of segregation. d. Accept or reject hypothesis Hypothesis 1 Aa: 1 aa 1 Bb: 1 bb z value P value e. In view of the z values obtained for each trait individually, how might you account for the dihybrid testcross ratio obtained?

Explanation / Answer

The value d^2/E is the chi square value. It is 319.69

Degree of freedom is 4-1=3

Probability is beyond 0.05%, means the hypothesis is rejected.

Phenotype O E O-E=d d^2 d^2/E AABB 102 9/16×331=186.19 -84.19 7087.95 38.06 AAbb 61 3/16*331=62.06 -1.06 1.12 0.018 aaBB 71 3/16*331=62.06 8.94 79.92 1.247 aabb 97 1/16*331=20.68 76.32 5824.74 280.30 Total 331 331 319.69

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