Each of the following vectors is given in terms of its x - and y -components. Pa

Question

Each of the following vectors is given in terms of itsx- and y-components.

Part A

vx = 15 m/s , vy = 43 m/s . Find the vector's magnitude.

Express your answer using two significant figures.

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Part B

vx = 15 m/s , vy = 43 m/s . Find the vector's direction.

Express your answer using two significant figures.

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Part C

ax = 3.5 m/s2 , ay = -4.0 m/s2 . Find the vector's magnitude.

Express your answer using two significant figures.

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Part D

ax = 3.5 m/s2 , ay = -4.0 m/s2 . Find the vector's direction.

Express your answer using two significant figures.

Part A

vx = 15 m/s , vy = 43 m/s . Find the vector's magnitude.

Express your answer using two significant figures.

v =   m/s  

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Part B

vx = 15 m/s , vy = 43 m/s . Find the vector's direction.

Express your answer using two significant figures.

=    above + x-axis

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Part C

ax = 3.5 m/s2 , ay = -4.0 m/s2 . Find the vector's magnitude.

Express your answer using two significant figures.

a =   m/s2  

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Part D

ax = 3.5 m/s2 , ay = -4.0 m/s2 . Find the vector's direction.

Express your answer using two significant figures.

=    below + x-axis

Explanation / Answer

given,

vx = 15 m/s , vy = 43 m/s

resultant vector = sqrt(vx^2 + vy^2)

resultant vector = sqrt(15^2 + 43^2)

resultant vector v = 45.541 m/s

angle = tan^-1(vy/vx)

angle = tan^-1(43/15)

angle = 70.77 degree above x axis

for vectors

ax = 3.5 m/s2 , ay = -4.0 m/s2

resultant vector = sqrt(ax^2 + ay^2)

resultant vector = sqrt(3.5^2 + (-4)^2)

resultant vector v = 5.315 m/s^2

angle = tan^-1(ay/ax)

angle = tan^-1(-4/3.5)

angle = 48.81 degree below x axis

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