Samples A and B are at different initial temperatures when they are placed in a

Question

Samples A and B are at different initial temperatures when they are placed in a thermally insulated container and allowed to come to thermal equilibrium. Figure (a) gives their temperature T versus time t. Sample A has a mass of 4.0 kg; sample B has a mass of 1.5 kg. Figure (b) is a general plot for material of sample B. It shows the temperature change T that the material undergoes when energy is transferred to it as heat Q. The change T is plotted versus the energy Q per unit mass of the material, and the scale of the vertical axis is set by Ts = 4.0°C. What is the specific heat of sample A?

Explanation / Answer

in the fig A

heat lost by A = heat gained by B

in the fig. B

the specific heat of sample B is 16 kJ/kg

so then the formula

specific heat A*mass A*temp drop A = specific heat B*mass B *temp rise B

16 * 10^3 * 4 * 60 = specific heat B * 1.5 * 20

specific heat B = 128 * 10^3 J/kg

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.