Three charged marbles are glued to a nonconducting surface and are placed in the

Question

Three charged marbles are glued to a nonconducting surface and are placed in the diagram as shown. The charges of each marble are q1 = 6.60 µC, q2 = 1.90 µC, and

q3 = 2.41 µC.

Marble q1 is a distance r1 = 3.00 cm to the left of the marble q2, while marble q3 is a distance r3 = 2.00 cm to the right of the marble q2, as shown. Calculate the magnitude of the electric field a distance r' = 1.00 cm to the left of the center marble.

Another marble is placed 1 cm to the left of the middle marble. If this new marble has a charge of

3.63 µC,

calculate magnitude and direction of the force on it.

Explanation / Answer

center marble is the marble2

So the electric field is E = k[(q1/r1)+(q2/r2)+q3/r3)]

E = (9*10^9)[(6.6*10^-6/0.02)-(1.9*10^-6/0.01)+(2.41*10^-6/0.03)]

E = 9000*(6.6/0.02)-(1.9/0.01)+(2.41/0.03)

E = 1.983*10^6 N/C towards the right direction

Force is F= q*E = 3.63*10^-6*1.983*10^6 = 7.2 N opposite to E....i.e left side of the marble q2

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