What is the net force exerted by these two charges on a third charge q 3 = 54.5

Question

What is the net force exerted by these two charges on a third charge q3 = 54.5 nC placed between q1 and q2 at x3 = -1.080 m ?

Force on q3 = N?

0=8.854×1012C2/(Nm2) is the permittivity of free space.

Consider two point charges located on the x axis: one charge, q1 = -19.5 nC , is located at x1 = -1.750 m ; the second charge, q2 = 40.0 nC , is at the origin (x=0.0000).

Force on q3 = N?

0=8.854×1012C2/(Nm2) is the permittivity of free space.

Consider two point charges located on the x axis: one charge, q1 = -19.5 nC , is located at x1 = -1.750 m ; the second charge, q2 = 40.0 nC , is at the origin (x=0.0000).

Explanation / Answer

Since Q1 is negative and to the left of Q3 the force will be to the left

Since Q2 is positive and to the right of Q3 the the force will also be to the left

Therefore you can add the forces together (with left being negative)

Now we have F = -k*Q1*Q3/r13^2 - k*Q2*Q3/r23^2

-9.0x10^9*19.5x10^-9*54.5x10^-9/(1.750 - 1.08)^2 - 9.0x10^9*40x10^-9*54.5x10^-9/1.08^2

F = -3.8 * 10^-5 N

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