Sherlock Holmes is using an 7.90-cm-focal-length lens as his magnifying glass. P

ID: 1403817 • Letter: S

Question

Sherlock Holmes is using an 7.90-cm-focal-length lens as his magnifying glass.

Part A

To obtain maximum magnification, where must the object be placed (assume a normal eye)?

Express your answer to three significant figures and include the appropriate units.

Part B

What will be the magnification?

Express your answer using three significant figures.

Sherlock Holmes is using an 7.90-cm-focal-length lens as his magnifying glass.

Part A

To obtain maximum magnification, where must the object be placed (assume a normal eye)?

Express your answer to three significant figures and include the appropriate units.

d0 =

Part B

What will be the magnification?

Express your answer using three significant figures.

M =

magnifying lense is nothing but converging lens

For converging lens the focal length is positive

then apply lens euqation

1/f = 1/di + 1/do

For maximum magnification the image must be formed at the near point of the eye

di = 25 cm

then do = (1/f - 1/di)^-1 = ((1/7.9)-(1/25))^-1
do = 11.54 cm
---------------------------------------------------

magnification M = -di/do = -25/11.54 = -2.166

taking positivevalue M = 2.16

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