Element X forms a face-centered cubic crystal structure. The density of the mate

Question

Element X forms a face-centered cubic crystal structure. The density of the material is 3200 kg/m^3. The atomic mass of one atom is 50 u.
A) How far apart are the nearest two atoms? B) What is the atomic separation if instead the crystal structure was a primitive cube?
Please show work! Thanks! Element X forms a face-centered cubic crystal structure. The density of the material is 3200 kg/m^3. The atomic mass of one atom is 50 u.
A) How far apart are the nearest two atoms? B) What is the atomic separation if instead the crystal structure was a primitive cube?
Please show work! Thanks! Element X forms a face-centered cubic crystal structure. The density of the material is 3200 kg/m^3. The atomic mass of one atom is 50 u.
A) How far apart are the nearest two atoms? B) What is the atomic separation if instead the crystal structure was a primitive cube?
Please show work! Thanks!

Explanation / Answer

p = nA/N0a^3

For fcc, n=4

a=0.464x10^-8m

For primitive or simple cube, n=1

a=0.296x10^-8m

a is the lattice parameter

N0 is Avogadro's no.

A is Atomic mass of element

Hope this helps !! All the best

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