Preview File Edit View Go Tools Window Help 61% D Wed Aug 5 2:43 PM a E old fin3

Question

Preview File Edit View Go Tools Window Help 61% D Wed Aug 5 2:43 PM a E old fin3b.gif Edited a Search A 6. Given the circuit as shown with E 10V,R1 4 R. R3 3 2, C 20 HP, Co- 40 uF. Switch Sis open and all capacitors are discharged. Then the switch is closed, Cz A. pts After the switch has been closed for a longtime, what will the current through R1 be? (Hint: Recall that once a capacitor is fully charged, no current passes through it TAns. 10A B. (10 pts) What will the charge on the upper plate of Cube after Shas beenclosed for a lengtime? Ans. 30 C, (5 pts) Ifss ritoh S:snowr orsened, what wriii be the time oonstant, T, for the deoay of the surrent. through Rz and R ns. 80 Hc

Explanation / Answer

A) After a long the capacitors acts as open ckts.

so, Rnet = R1 + R2 + R3

= 4 + 3 + 3

= 10 ohms

so, current through R1, I = V/Rnet

= 10/10

= 1 A

b) After a long time potential diffrence between point a and b, Vab = I*(R+R3)

= 1*(3+3)

= 6 volts

here C1 and C2 are connected in series,

so, Cnet = C1*C2/(C1+C2)

= 20*40/(20+40)

= 13.333 micro F

Here charge on C1 and C2 are same. beacuse they are connected in series.

so, charge on C1 = charge on C2 = Cnet*Vab

= 13.333*10^-6*6

= 80*10^-6 C

= 80 micro c

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