Let R(big = 54321 ohms and R(small) = 0.54321 ohms Find the series and parallel

Question

Let R(big = 54321 ohms and R(small) = 0.54321 ohms

Find the series and parallel combinations of these two resistors. b) When there is a large difference in two resistor’s sizes, what useful approximations can be used when considering their series and parallel combinations?

Measurements Check 1 Check 2 Measurements Check 3 Check 4 Check 5 Check 7 , exp (mA) Check 6 Measurements emf,dm .dm .dm Vi,dmLoop LawVf , exp 3.24550.2966 4.7659 10.064 2.1 10.064 6.848 2.214 1.001 10.0630 1.39 0.42 -0.95 lath-Vi/R, (mA) emf,th 2,th ,th (k2) (k2) (k2) (mA) (V 10.012 (mA) (mA) (mA) (mA) 6.816 4.5449 1.39 1.40036974 -0.436230090.96455696 2, exp (mA)0.74602466 3.864306381.532311792 1.04830.2966 4.7678 2.1 2.11166831 2.201 0.995 | 0 0.03985 96 diffs, 96 diff, 0.55256359 0.51669 0.46728972 0.58717 96 diff, % diff 96 diff 96 diffb % diffe % diff,c | 0.5994 % diff, 96 diffsb 1.dm (k2) 0.474 6.848 0.45730.42 l, exp (k2) (mA) 0.2966 2.214 0.4572 0.95 ,dm (k2) 4.7659 1.001

Explanation / Answer

a) When two resistor are in series combination then their equilaent resistance will be found by using formula given below

Req = R1+R2 = 54321 + 0.54321 = 54321.54321 ohm

When two resistors are in parrallel combination then their equivalent resistance could be found by using the following formula

1/Req = 1 / R1 + 1 / R2

Req = R1R2 / R1 + R2

Req = 54321(0.54321) / 54321+0.54321

Req = 0.54320 ohm

b) When there is the large difference between the resistors are present and if resistors are in seires combination then we can use the following approximation.

R1 is very very very greater than R2 , then

Req is nearly equals to R1.

If Resistors are in parrallel and R1 is very very very greater than R2 , then

Req is nearly equals to R2.

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