The graph below shows a thermodynamic process for a monoatomic ideal gas in a se
ID: 1402476 • Letter: T
Question
The graph below shows a thermodynamic process for a monoatomic ideal gas in a sealed container. At the start of the process (point 1) the temperature of the gas is Ti. What are the temperatures of the gas at points 2 and 3 expessed as multiples of the initial temperature Ti?
T2 = Ti/2
T3 = 3Ti/2
T2 = Ti
T3 = 3Ti/2
T2 = Ti/2
T3 = Ti
T2 = Ti
T3 = 2Ti
T2 = Ti/3
T3 = 3Ti/2
A).T2 = Ti/2
T3 = 3Ti/2
B).T2 = Ti
T3 = 3Ti/2
C).T2 = Ti/2
T3 = Ti
D).T2 = Ti
T3 = 2Ti
E).T2 = Ti/3
T3 = 3Ti/2
Pressure 3P 2 Volume V,/2 ViExplanation / Answer
Answer is B) T2= Ti; T3= 3 Ti/2
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