Reduce by one-half the slit separation.Double the slit separation.Double the sep

Question

Reduce by one-half the slit separation.Double the slit separation.Double the separation between the screen and the slits.Reduce by one-half the separation between the screen and the slits.Green light of wavelength 540 nm is incident on two slits that are separated by 0.20 mm .

a) Determine the frequency of the light. Express your answer to two significant figures and include the appropriate units.

b) Determine the angles of the first two maxima of the interference pattern. Enter your answers in order of increasing of angles separated by commas. Express your answer using two significant figures.

c) What can you change in order to double the distance between the 0th and the first bright spot on the screen?

Choose all that apply:

1.Reduce by one-half the slit separation.

2.Double the slit separation.

3.Double the separation between the screen and the slits.

4.Reduce by one-half the separation between the screen and the slits.

Explanation / Answer

a) Apply, c = lamda*f (here c light speed, lamda is wavelength and f is frequency)

f = c/lamda

= 3*10^8/(540*10^-9)

= 5.56*10^14 Hz

b) for first maxima, d*sin(theta) = 1*lamda (here d is slit separation)

sin(theta) = lamda/d

theta = sin^-1(lamda/d)

= sin^-1(540*10^-9/(0.2*10^-3))

= 0.1547 degrees

for second maxima, d*sin(theta) = 2*lamda (here d is slit separation)

sin(theta) = 2*lamda/d

theta = sin^-1(2*lamda/d)

= sin^-1(2*540*10^-9/(0.2*10^-3))

= 0.3094 degrees

c) distance from center to first bright spot, y = lamda*R/d (here R is distance from slts to screen)

1.Reduce by one-half the slit separation.

3.Double the separation between the screen and the slits.

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