A spring lies on a horizontal table, and the left end of the spring is attached

Question

A spring lies on a horizontal table, and the left end of the spring is attached to a wall. The other end is connected to a box. The box is pulled to the right, stretching the spring. Static friction exists between the box and the table, so when the spring is stretched only by a small amount and the box is released, the box does not move. The mass of the box is 0.75 kg, and the spring has a spring constant of 59 N/m. The coefficient of static friction between the box and the table on which it rests is s = 0.66. How far can the spring be stretched from its unstrained position without the box moving when it is released?

Explanation / Answer

let x is the extension of the spring.

here,

force exerted by the spring = maximum static frctional force

k*x = mue_s*N

k*x = mue_s*m*g

x = mue_s*m*g/k

= 0.66*0.75*9.8/59

= 0.0822 m or 8.22 cm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.