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5. (15 heat m. 10 Three point are accelerated the origin; in engine? first charg

ID: 1400435 • Letter: 5

Question

5. (15 heat m. 10 Three point are accelerated the origin; in engine? first charge, of the net through a potential -2.00 x constant m at force. located is at The HC, x is 15.0 them 10.0 HC, direction by sending charge the an gun the electron The third and and on x-axis. the rest of the magnitude the from a is HC, on diagram the are q2? is efficiency located at Show +30.0 charges What force q2 net J. N.m2/C2. Draw electrons of is 2200 What the charge, If output 8.99x points). second points). k +1.00 (30 the a difference of 1000 V, what is the speed of the electrons? and nlote separation of 0.20 mm. The

Explanation / Answer

given,

charges 15 * 10^-6 C, 30 * 10^-6 C, -10 * 10^-6 C

at x = -2m, 0m, 1m

force = k * q1 * q2 / r^2

force between q1 and q2 = 8.99 * 10^9 * 15 * 10^-6 * 30 * 10^-6 / 2^2

force between q1 and q2 = 1.011375 N

force between q2 and q3 = 8.99 * 10^9 * 30 * 10^-6 * -10 * 10^-6 / 1^2

force between q2 and q3 = -2.697 N

net force = 1.011375 + (-2.697)

net force = -1.685625 N

net force = 1.685625 direction is toward q3

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