1. An electrical motor spins at a constant 1121 rpm. If the armature radius is 4
ID: 1400342 • Letter: 1
Question
1.
An electrical motor spins at a constant 1121 rpm. If the armature radius is 4.8 cm, what is the acceleration of the edge of the rotor?
2.
A glass flask has a volume of 700 ml at a temperature of 20° C. The flask contains 697 ml of mercury at an equilibrium temperature of 20°C. The temperature is raised until the mercury reaches the 700 ml reference mark. The coefficients of volume expansion of mercury and glass are 18 x 10-5 K-1 and 2.0 x 10-5 K-1, respectively. The temperature at which this occurs, in °C, is closest to:
7.3 m/s2 72.7 m/s2 66350 m/s2 661.5 m/s2Explanation / Answer
1)
given,
angular speed, w=1121 rev/min
w=1121*(2pi/60) rad/sec
w=117.33 rad/sec
radius, r=4.8 cm
acceleration a=r*w^2
= 4.8*10^-2*(117.33)^2
= 661 m/sec^2
2)
volume of the glass flask v1=700 ml at temperature T1=20 oc
volume of mercury v1'=697 ml at temperature T1=20 oc
volume of mercury v2'=700 ml at temperature T2=?
here,
final volume (v2) of the flask and mercury is same,
and
v2=v1(1+gamma_glass*(T2-T1))
v2'=V1'(1+gamma_mercuty*(T2-T1))
now,
v2=-v2'
v1(1+gamma_glass*(T2-T1))=-v1'(1+gamma_mercuty*(T2-T1))
700(1+18*10^-5*(T2-20))=-697(1+2*10^-5*(T2-20))
1.0043(1+18*10^-5*(T2-20))=-(1+2*10^-5*(T2-20))
====>
T2=46.77 oC
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