PLEASE EXPLAIN! I have tried this problem multiple times to no avail. Thanks for

Question

PLEASE EXPLAIN! I have tried this problem multiple times to no avail. Thanks for the help, your'e the best.

A particle with an initial linear momentum of 3.34 kg · m/s directed along the positive x-axis collides with a second particle, which has an initial linear momentum of 6.68 kg · m/s, directed along the positive y-axis. The final momentum of the first particle is 5.01 kg · m/s, directed 45.0° above the positive x-axis. Find the final momentum of the second particle.

Explanation / Answer

let the final momentum of second particle is pf

Now, as there is no external force acting on the particles ,

Using conservation of momentum

initial momentum = final momentum

3.34 i + 6.68 j = pf + 5.01 *(cos(45) i + j * sin(45) )

now , soloving for pf

pf = -0.202 i + 3.14 j Kg.m/s

magnitude of momentum = sqrt(0.202^2 + 3.14^2)

magnitude of momentum = 3.146 Kg.m/s

theta = arctan(3.14/.202)

theta = 86.32 degree above negative x-axis

the momentum of second particle is 3.146 Kg.m/s at 86.32 degree above negative x-axis

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