Problem 20.02 Part A An ion having charge +6e is traveling horizontally to the l

Question

Problem 20.02 Part A An ion having charge +6e is traveling horizontally to the left at 8.20 km/s when it enters a magnetic field that is perpendicular to its velocity and deflects it downward with an initial magnetic force of 6.84x10-15 N What is the direction of this field? The field is directed out of the screen. The field is directed into the screen The field is directed to the right. The field is directed tot he left. Submit My Answers Give Up Correct Part B What is the magnitude of this field? Submit My Answers Give Up Continue

Explanation / Answer

here,

(b)

charge on ion , q = 6e

speed of ion , v = 8.2 km/s

v = 8.2 * 10^3 m/s

the magnetic force , F = 6.84 * 10^-15 N

let the magnetic feild be B

F = q *v * B sin(90)

6.84 * 10^-15 = 6 * 1.6 * 10^-19 * 8.2 * 10^3 * B

B = 0.869 T

the magnitude of magnetic feild is 0.869 T

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